Wednesday, August 05, 2009

Axapta : Array object


array i;
int n;
;

i = new array(types::String);

i.value(1,"1.");
i.value(2,"2.");
i.value(3,"3.");
i.value(4,"4.");


for(n =1; n <= i.lastIndex(); n++)
print i.value(n);

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